
PlanningGuide
Module
4
Lesson 1.13
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Lesson 1.13
Lesson 1.14
Lesson 1.15
Lesson 1.16
Lab 1.13
Lab 1.14
Lab 1.15
Lab 1.16
Project 4
Module 1
Module 2
Module 3
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LESSON 1.13 - COLLISIONS
Overview
This lesson deals with
the conservation of momentum when two or more objects
interact. On completion of the lesson, you should be able
to calculate the velocities of objects after elastic and
inelastic collisions. You should also be able to describe
typical elastic and inelastic collisions and discuss the
vectors involved in collisions.

ACTIVITIES
- Match Projectiles:
Use a drinking straw as a blowpipe to launch
matches at a target. Shorten the straw by cutting
a piece off the straw and see how this affects
the range of the blowpipe.
- Use marbles or pool
balls to illustrate how momentum is conserved
during collisions.


Systems
A system is a defined collection of objects. It is common
to define a system in terms of a boundary around the
system. In dealing with collisions, the system usually
consists of the objects that collide. Another system
could be a rifle that is at rest before a projectile is
fired from it. The rifle and the projectile make up the
system. After the item is fired both the rifle and the
bullet move.
Conservation of
Momentum
The net momentum of a system does not change. If a moving
object collides with a stationary object, the combined
momentum of the two objects after collision is the same
as the momentum of the moving object before collision. If
a rifle is fired, the momentum of the bullet in one
direction cancels the momentum of the rifle as it moves
in the opposite direction.
Types of Collisions
Collisions can be elastic, inelastic or a combination of
the two. In an elastic collision, no energy is lost
during the collision. In an inelastic collision, some
energy is coverted to other forms but momentum is
conserved. If a bullet hits a sandbag that is hanging on
a piece of rope, the sand will absorb some of the bullets
energy but the combined momentum of the bag and the
bullet will be nearly the same as the momentum of the
bullet before collision.
Momentum Vectors
If objects collide in such a way that their directions
differ after collision from the directions of the
colliding objects, the net momentum an any direction will
be the same as before the collision. For example, if a
moving pool ball collides with a stationary pool ball and
both move off at an angle, the components of their
momenta in different directions will either be the same
as the momentum of the first moving ball or they will
cancel out.

Example 1.13.1
Collision
A freight car with a mass of 9000 kg moving along a track
at 2 m/s collides elastically with a stationary freight
car with a mass of 10,000 kg and stops.
- Assuming that no
momentum is lost during the collision, what will
be the speed of the second railcar after the
collision?
- If the cars hook
together during the collision and the collision
can be regarded as inelastic, what will be the
speed of both cars after the collision?
Solution
a) The momentum of the
first freight car = 9000 x 2 = 18000 kg-m/s
If it stops on collision,
the second railcar must absorb a momentum of 18000 kg-m/s
The second cars
velocity must therefore be = (18000 kg-m/s) / (10000 kg)
= 1.8 m/s
b) The momentum of the
freight car = 9000 x 2 = 18000 kg-m/s
The combined momentum
after the collision must be = 18000 kg-m/s
The combined mass of the
two cars is 19000 kg.
The velocity must
therefore be = (18000 kg-m/s) / (19000 kg) = 0.947 m/s

Review
Questions
- If two glass marbles
collide, is the collision likely to be elastic or
inelastic?
- If a railcar moving
along a track collides with a second railcar and
the couplings join during the collision, is the
collision regarded as elastic or inelastic?
- A system consists of
a person standing on a skateboard holding a large
rock. If nothing in the system moves, what is the
momentum of the system?
- If the person throws
the rock away from the skateboard in a direction
in line with the wheels, will the skateboard
move?
If it moves, in what direction will it move?
- If the rock has a
mass of 20kg and it leaves the persons
hands with a velocity of 2 m/s, what will be the
combined momentum of the person and the
skateboard as the rock leaves the persons
hands? Why?
- A marble with a mass
of 15 grams moving at 2 m/s collides with an
identical marble that is at rest. After the
collision, the first marble is at rest. What is
the speed of the second marble after the
collision?
- A marble with a mass
of 15 grams swinging on the end of a piece of
string and moving at 2.5 m/s collides with a lump
of putty that is attached to the end of a second
piece of string. The putty has a mass of 20 grams
and is stationary prior to the collision. What is
the combined momentum of the putty and marble
after the collision?
- A marble rolls down a
chute and collides with a stationary marble with
the same mass at the edge of a table. If the
arrow, A, in the diagram below indicates the
velocity of the marble prior to collision and B
indicates the velocity of the stationary marble
after collision, draw an arrow that roughly
indicates the direction of the first marble after
collision.


ACTIVITIES
- Match Projectiles:
Use a drinking straw as a blowpipe to launch
matches at a target. Shorten the straw by cutting
a piece off the straw and see how this affects
the range of the blowpipe.
- Use marbles or pool
balls to illustrate how momentum is conserved
during collisions.
.
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HANDS-ON
HOMEWORK
Select one or more of the recommended
activities for Lesson 1.14, collect the items needed and test the
procedure before demonstrating the activity during the
next theory lesson.

Lesson
1.13 Collisions
- Mainly elastic.
- Inelastic.
- Zero
- Yes. In the opposite
direction to the rock.
- The momentum of the
person and the skateboard will be the same as
that of the rock but in the opposite direction.
The net momentum must be the same after the rock
has been thrown as it was before the rock was
thrown because nothing outside of the system (consisting
of the person, the rock and the skateboard) has
influenced the system. The momentum of the person
and the skateboard will be equal to 20kg x 2 m/s
= 40 kg-m/s.
- 2 m/s. All of the
momentum from the first marble will have been
transferred to the second marble.
- Momentum before
collision = 0.015kg x 2 m/s = 0.03 kg-m/s. The
momentum of the system after collision must be
the same. the combined mass is 0.015kg + 0.02kg =
0.035 kg.
The velocity just after impact will be = 0.03 / 0.035
= 0.857 m/s
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